一数组有172个元素，在CCS平台下要分两个数组才能完整查找：例子如下
#include <16F877A.h>
#device adc="8"
#FUSES NOWDT //No Watch Dog Timer
#FUSES HS //High speed Osc (> 4mhz for PCM/PCH) (>10mhz for PCD)
#FUSES NOPUT //No Power Up Timer
#FUSES NOPROTECT //Code not protected from reading
#FUSES NODEBUG //No Debug mode for ICD
#FUSES NOBROWNOUT //No brownout reset
#FUSES NOLVP //No low voltage prgming, B3(PIC16) or B5(PIC18) used for I/O
#FUSES NOCPD //No EE protection
#FUSES NOWRT //Program memory not write protected
#use delay(clock=4000000)
#use rs232(UART1,baud=9600,parity=N,bits=8)
const unsigned int16 sinetable1[] =
{999,201,401,602,803,1003,1204,1404,1605,1805,
2005,2206,2406,2606,2806,3006,3205,3405,3605,3804,4003,4202,4401,4600,
4799,4997,5195,5393,5591,5789,5986,6183,6380,6577,6773,6970,7166,7361,
7557,7752,7947,8141,8335,8529,8723,8916,9109,9302,9494,9686,9877,10068,
10259,10449,10639,10829,11018,11207,11395,11583,11771,11958,12144,
12331,12516,12701,12886,13070,13254,13437,13620,13802,13984,14165,
14346,14526,14706,14885,15063,15241,15419,15595,15772,15947,16122,
16297,16470,16643,16816,16988,17159,17330,17500,17669,17838,18006,
18173,18340,18506,18671,18835,18999,19162,19325,19487,19647,19808,
19967,20126,20284,20441,20598,20753,20908,21062,21216,21368,21520,
21671,21821,21970,22119,22266,22413,22559,22704,22848,22992};
const unsigned int16 sinetable2[] =
{23134,23276,23417,23557,23696,23834,23971,24107,24243,24377,24511,
24644,24776,24906,25036,25165,25293,25420,25547,25672,25796,25919,
26042,26163,26283,26403,26521,26638,26755,26870,26984,27098,27210,
27321,27431,27541,27649,27756,27862,27967,28071,28174,28276,28377};
unsigned int16 Speed,Amplitude;
unsigned int8 Phase;
void main()
{
setup_adc_ports(NO_ANALOGS);
setup_adc(ADC_OFF);
setup_psp(PSP_DISABLED);
setup_spi(SPI_SS_DISABLED);
setup_timer_0(RTCC_INTERNAL|RTCC_DIV_1);
setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
setup_comparator(NC_NC_NC_NC);
setup_vref(FALSE);
Speed="64";
while(TRUE){
delay_ms(80);
Phase +=Speed;
if (Phase>171) Phase="Phase-171";
if (Phase >=128 )
Amplitude="sinetable2"[Phase-128];
if (Phase<128)
Amplitude="sinetable1"[Phase];
printf("\r\n");
printf("Phase %u ",Phase);
printf("Amplitude %Lu\r\n",Amplitude);
}
}